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Absolute Value Inequalities Calculator

The bars measure distance, and an absolute value inequality asks how far is still acceptable. This absolute value inequalities calculator takes the three numbers in $|ax + b| < c$ - or $>$, $\le$, $\ge$ - and returns the two endpoints that bound the answer. One click decides the endpoints and their joining word together.

Fill |ax + b| ? c, then pick the inequality sign from the dropdown.

|x+|
Type an absolute value inequality like |2x + 1| <= 9 - the AI will fill the form and explain every step

How to use this absolute value inequalities calculator

Fill four boxes, click Calculate. This absolute value inequalities calculator solves the standard form ∣ax+b∣  □  c|ax + b| \;\square\; c, and the dropdown picks the sign in the middle. Fill the boxes as the letters appear in your problem and press Calculate once. One pass of the absolute value inequalities calculator settles the question - no case sorting, no second run.

  • Coefficient of x (a) - the number multiplying xx inside the bars, such as 2 in ∣2x+1∣≤9|2x + 1| \le 9; a negative aa goes in as-is - the absolute value inequalities calculator keeps your sign
  • Constant (b) - the number added to axax, such as 1
  • Right-hand side (c) - the number on the far side of the sign, such as 9, which the absolute value inequalities calculator compares against ax+bax + b
  • Comparison sign - choose <<, >>, ≤\le or ≥\ge; the absolute value inequalities calculator uses it to shape the answer

Three rows come back. Endpoint 1 solves ax+b=cax + b = c and Endpoint 2 solves ax+b=−cax + b = -c. Together they are the two edges of the answer, and the absolute value inequalities calculator prints both at once, matched to the +c+c and −c-c branches of the table below. The band width row prints 2c/∣a∣2c/|a|, the length of the stretch, so you can check the endpoints against it at a glance. If the two endpoint rows ever come out equal, the absolute value inequalities calculator is telling you the answer has collapsed to a single point - a band width of zero.

Reading the rows is where the absolute value inequalities calculator saves you the case sorting. For a less-than problem the answer is the stretch between the two endpoints. For a greater-than problem the answer is two rays running outward. The absolute value inequalities calculator still finds the same two edges - only the joining word changes, from and to or.

This page is more than a static absolute value inequalities calculator - it is also an AI tutor: the question box takes plain words, homework photos, and follow-ups. Ask it to fill the four boxes from a word problem. The absolute value inequalities calculator then runs on exactly the numbers the AI typed in, so audit each field before trusting the result. Ask it to explain any step in words. Every number still comes from the form on this page.

One habit makes the absolute value inequalities calculator twice as useful: read cc before you press Calculate. A negative cc changes the whole story - read it first, and the absolute value inequalities calculator's rows will always mean what you expect. The sections below show exactly how.

What an absolute value inequality really asks

Read the bars as a distance. ∣2x+1∣≤9|2x + 1| \le 9 asks: which xx keep the value 2x+12x + 1 within 9 steps of zero? Each qualifying xx sits in one connected stretch of the number line. An absolute value inequalities calculator exists to pin down the two ends of that stretch, and this absolute value inequalities calculator does it from three numbers and a sign. The absolute value inequalities calculator turns that single question into two boundary equations, and nothing else.

The picture shows the answer to ∣2x+1∣≤9|2x + 1| \le 9: a closed dot at −5-5, a closed dot at 44, and every point between them shaded. The absolute value inequalities calculator confirms the same pair from a=2a = 2, b=1b = 1, c=9c = 9. Asked which xx qualify, the answer is exactly the shaded band. Reading the drawing beside the rows is the absolute value inequalities calculator showing the same answer twice.

Distance also explains why the answer never falls into three or more pieces. A distance either fits inside its bound or it does not, so one run of the absolute value inequalities calculator sorts every point on the line into in or out. That is why a single run of the absolute value inequalities calculator is always enough.

-7-6-5-4-3-2-10123456-5 ≤ x ≤ 4

Solution set of |2x + 1| ≤ 9 on the number line: closed dots at -5 and 4, shading over the whole band between them - the and-case answer the absolute value inequalities calculator confirms from a = 2, b = 1, c = 9

The two-branch rule: and or or

One table runs the whole topic. For an expression uu inside the bars and a positive bound cc, the rewrite is fixed - and the absolute value inequalities calculator applies it before anything else. This table is also the wiring inside the absolute value inequalities calculator.

FormRewrites asJoined by
$u< c$
$u\le c$
$u> c$
$u\ge c$

Less-than signs keep the answer between the two edges: one stretch, joined by and. Greater-than signs push it outside: two rays, joined by or. Every absolute value inequalities calculator is an application of this split. The table also explains the two endpoint rows - they are the −c-c edge and the +c+c edge that the absolute value inequalities calculator solves for.

The letters on this page match the form fields exactly, so a problem can be copied straight into the absolute value inequalities calculator:

LetterMeaning
aacoefficient of xx inside the bars (field a)
bbconstant added to axax (field b)
ccright-hand side (field c)

Where the two endpoints come from

The endpoints solve the two boundary equations at once. Where ax+b=cax + b = c, x=c−bax = \dfrac{c - b}{a}. Where ax+b=−cax + b = -c, x=−c−bax = \dfrac{-c - b}{a}. Those two values are the first two rows the absolute value inequalities calculator returns, in that order - one absolute value inequalities calculator pass, both boundaries solved. The third row is the band width 2c∣a∣\dfrac{2c}{|a|} - the gap between the two endpoints, taken as the absolute value of their difference.

Which endpoint lands on the left depends on the sign of aa. With a=2a = 2, b=1b = 1, c=9c = 9 the rows come out as 44 and −5-5, so −5-5 is the left edge. Change to a=−2a = -2 and the absolute value inequalities calculator hands back the same pair in mirrored order. Sorting them by hand is the one step the absolute value inequalities calculator leaves to you.

The workflow stays short either way. Sort the two endpoint values, then let the and/or table decide what the absolute value inequalities calculator should draw between them and beyond them.

Three edge cases worth knowing

Three kinds of input deserve a second look before you trust any output of the absolute value inequalities calculator.

  • Negative cc with << or ≤\le. A distance is never negative, so ∣2x−1∣<−4|2x - 1| < -4 has no solution. The endpoint rows still compute, but nothing satisfies the inequality - the absolute value inequalities calculator cannot read cc for you.
  • Negative cc with >> or ≥\ge. The reverse: ∣x+3∣>−2|x + 3| > -2 is true for every real xx, because a distance is always zero or more - the endpoint rows still compute, and the or-rule then lets every real xx qualify.
  • a=0a = 0. The bars then hold a bare constant such as ∣5∣<9|5| < 9, and there is no xx left to solve for. Keep aa nonzero so the absolute value inequalities calculator sees a real expression in xx.

Example 1 - the and-case, |2x + 1| ≤ 9

Solve ∣2x+1∣≤9|2x + 1| \le 9, then write the answer three ways.

  1. Split: −9≤2x+1≤9-9 \le 2x + 1 \le 9 - a less-than case, so one stretch joined by and.
  2. Subtract 1 from all three parts: −10≤2x≤8-10 \le 2x \le 8.
  3. Divide by 2: −5≤x≤4-5 \le x \le 4 - the same pair the absolute value inequalities calculator prints. In interval notation: [−5,4][-5, 4].

Now let the absolute value inequalities calculator confirm it with a=2a = 2, b=1b = 1, c=9c = 9. Endpoint 1 reads 9−12=4\dfrac{9 - 1}{2} = 4 and Endpoint 2 reads −9−12=−5\dfrac{-9 - 1}{2} = -5 - the same pair, delivered without any case sorting. The band width row prints 2⋅92=9\dfrac{2 \cdot 9}{2} = 9, and indeed 4−(−5)=94 - (-5) = 9. Spot-check an interior point: x=0x = 0 gives ∣1∣=1≤9|1| = 1 \le 9, true as promised. The figure above also shows what ≤\le buys you: both endpoints are solid dots, which is exactly how the absolute value inequalities calculator marks an edge that counts.

Example 2 - the or-case, |3x + 6| ≥ 12

Solve ∣3x+6∣≥12|3x + 6| \ge 12, then describe the solution set.

  1. Split into two branches: 3x+6≥123x + 6 \ge 12 or 3x+6≤−123x + 6 \le -12.
  2. First branch: 3x≥63x \ge 6, so x≥2x \ge 2.
  3. Second branch: 3x≤−183x \le -18, so x≤−6x \le -6. Answer: x≤−6x \le -6 or x≥2x \ge 2.

Set a=3a = 3, b=6b = 6, c=12c = 12 in the absolute value inequalities calculator. Endpoint 1 is 12−63=2\dfrac{12 - 6}{3} = 2 and Endpoint 2 is −12−63=−6\dfrac{-12 - 6}{3} = -6, so the picture below needs no editing: closed dots at −6-6 and 22, shading outward on both sides. The absolute value inequalities calculator found the same two edges your algebra did. Run it again with c=11c = 11 and the right edge slides from 22 to 53\dfrac{5}{3} - the absolute value inequalities calculator tracks the bound as cc moves.

Only the sign changed from Example 1 - ≤\le became ≥\ge - and the answer moved from one band to two rays. That is exactly the difference the absolute value inequalities calculator exists to get right. Ask it for both cases and compare the two drawings.

-8-7-6-5-4-3-2-101234x ≤ -6 or x ≥ 2

Solution set of |3x + 6| ≥ 12: closed dots at -6 and 2 with shading outward on both sides - the or-case answer, two rays joined by or, exactly as the absolute value inequalities calculator draws it from a = 3, b = 6, c = 12

Three common mistakes with absolute value inequalities

Each of these slips survives sloppy algebra but not a careful pass through the absolute value inequalities calculator.

  1. Solving only the positive branch. From ∣3x+6∣≥12|3x + 6| \ge 12, keeping just x≥2x \ge 2 loses half the answer. Every x≤−6x \le -6 works too - test x=−7x = -7: ∣−15∣=15≥12|-15| = 15 \ge 12. The two endpoint rows always come as a pair, so the absolute value inequalities calculator makes the loss visible.
  2. Writing the band backwards. From −9≤2x+1-9 \le 2x + 1 some students continue with 9≥2x+1>−99 \ge 2x + 1 > -9 and end up chaining the signs in mixed directions. Keep one direction per line, or let the two endpoint rows of the absolute value inequalities calculator keep the order straight for you.
  3. Ignoring a negative right-hand side. Announcing that ∣2x−1∣<−4|2x - 1| < -4 solves to some pair of endpoints forgets that the bars never produce a negative. Check cc first: negative with << means no solution, negative with >> means everything - the absolute value inequalities calculator will print rows either way.

The absolute value inequalities calculator returns its endpoint rows side by side, so mistakes 1 and 2 surface the moment you compare them. Mistake 3 is the one check no absolute value inequalities calculator can do for you - read the sign of cc before you press Calculate.

Problem 1

A community pool tracks hh, its water temperature in °C. The heater runs at its safest setting while ∣2h−14∣≤6|2h - 14| \le 6. What is the highest temperature at which the heater still counts as safe? Set a=2a = 2, b=−14b = -14, c=6c = 6 and let the absolute value inequalities calculator hand you the endpoints, then read the higher one off the absolute value inequalities calculator's two rows.

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Problem 2

A lab sample cools to −4m+60-4m + 60 °C after mm minutes. It may be sealed only once the temperature has left the danger band, that is, once ∣−4m+60∣≥12|-4m + 60| \ge 12. Sealing during the early window is against protocol, so use the later window: what is the earliest whole number of minutes after which sealing is allowed? Enter a=−4a = -4, b=60b = 60, c=12c = 12 and the absolute value inequalities calculator gives both windows. Check the later one against the absolute value inequalities calculator's endpoint rows before answering.

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Frequently asked questions

1

Is a modulus inequality solver different from an absolute value inequalities calculator?

No. Modulus is another name for the same bars: $|3x + 6|$ and mod(3x + 6) both mean distance from zero. A modulus inequality solver and an absolute value inequalities calculator therefore take the same input and return the same two endpoints. Whichever name your textbook uses, read off $a$, $b$, $c$ and the sign - the four boxes on this page do the rest. Whichever label your homework prints, an absolute value inequalities calculator reads the bars the same way. If your source writes mod(3x + 6) >= 12, the absolute value inequalities calculator still sees the same problem - nothing needs rephrasing.

2

When should I reach for an equation solver with absolute value instead?

Look at the sign in the middle. An equals sign means you want the two exact points where the bars hit $c$. That is a job for a solving absolute value equations solver - our absolute value equations calculator page is built for exactly that. An inequality sign means you want a whole stretch or a pair of rays, which is what this absolute value inequalities calculator returns. In short: the equation page answers where exactly, and this page answers between where and where. One run of the absolute value inequalities calculator never mixes the two jobs.

3

When does an absolute value inequality have no solution?

When the right-hand side is negative and the sign demands the impossible. $|2x - 1| < -4$ has no solution, because the bars never hold a negative number. Flip the comparison and the opposite happens: $|x + 3| > -2$ is true for every real $x$. The absolute value inequalities calculator still prints its endpoint rows in these cases, so read $c$ first and decide whether those endpoints mean anything. Treat the negative-$c$ check as the one shortcut the absolute value inequalities calculator cannot take for you. With $<$, the empty set is already the final answer - say so and skip the run.

4

Why does this absolute value inequalities calculator return two endpoints instead of one answer?

Because a distance has two edges. The solutions stop where $ax + b = c$ and where $ax + b = -c$, so two boundary points come out of every run. The sign between decides what to do with them, and the absolute value inequalities calculator shows both edges before that choice happens. With $<$ or $\le$ the answer runs between the endpoints; with $>$ or $\ge$ it runs outside on both sides. That is also why the band width is printed - it shows whether the endpoints sit close together or far apart, at one glance. Those two rows are how the absolute value inequalities calculator names the edges it found.

5

What if a constant sits outside the bars, like |2x - 5| + 3 > 4?

Isolate the bars first, because the absolute value inequalities calculator expects the standard form. Subtract 3 from both sides and the problem becomes $|2x - 5| > 1$, which is exactly the standard form. Then enter $a = 2$, $b = -5$, $c = 1$. One tidy-up step, one normal run - no special settings needed anywhere on the absolute value inequalities calculator. After the tidy-up, the absolute value inequalities calculator treats $|2x - 5| > 1$ like any other entry.

6

Does the absolute value inequalities calculator draw the answer?

It does, on the number line - the two worked examples on this page show both shapes the absolute value inequalities calculator can draw. The and-case is a shaded band between two closed dots, and the or-case is two shaded rays. Closed dots mean the endpoint is included; a strict sign would draw hollow ones instead. Reading the drawing next to the endpoint rows of the absolute value inequalities calculator is the fastest way to catch a branch you forgot.

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